Sorting and Comparing Two Numbers in Java

there are 3 scenarios in comparing two numbers with each other

1. a>b

2. a<b

3. a=b

Let's write a program that takes two numbers from user and compares these numbers, taking into account the three scenarios above

Scanner input = new Scanner(System.in);
System.out.println("What is the first number?");
int a = input.nextInt();

System.out.println("What is the second number?");
int b = input.nextInt();

if (a > b)
	System.out.println(a+">"+b);
else if (a < b)
	System.out.println(a+"<"+b);
else
	System.out.println(a+"="+b);

Output Scenario 1:

What is the first number?
7
What is the second number?
6
7>6

Output Scenario 2:

What is the first number?
2
What is the second number?
5
2<5

Output Scenario 3:

What is the first number?
3
What is the second number?
3
3=3